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January 11, 2012

Write an assembly language program find largest number in array of data.

Written by @
Apparatus Used: Microprocessor Kit, Keyboard
Assumption: Let assume that We have to write a program to find largest number among 10 data. Data are stored at different memory location and we have to store largest number at memory location also.
Algorithm:
  • Load data for counter in first memory location
  • Get First Number and store it in accumulator
  • Decrement the counter by 1
  • Get second Number
  • Compare first and second number
  • Check for the carry if carry generated then second number is greater otherwise first number will be greater
  • If second number is greater then move it into Accumulator otherwise store output.
  • Decrement counter again
  • Check value of Counter=0, if counter is zero then end the program, otherwise proceed
  • End the Program
Program:
Memory Address
Op-code
Operand
Comments
2000
LXI
H,2500 H
Number of data at 2500 H
2003
MOV
C,M
Number of data as Counter
2004
INX
H
Get the first number
2005
MOV
A,M
Get First data in Accumulator
2006
DCR
C
Decrement Count
2007
INX
H
Get Second data to compare
2008
CMP
M
Compare First and Second
2009
JNC
200D
Jump if no carry
200C
MOV
A,M
Store output at 2052
200D
DCR
C
Store Carry in A
200E
JNZ
2007
Store carry at 2053
2011
STA
2550
Store largest number
2014
RST
5
Set Break-point
2015
END

End the program

Used Instruction:
LXI: This instruction is used to store the 16-bit data in the register pair designated in the operand.
MVI: This instruction is used to store 8 bit data in specified register.
MOV: This instruction is used to copy the content from source register to destination register.
INX: This instruction is used to increment the content of specified register pair by one.
DCR: This instruction is used decrement the content of specified register by 1.
CMP M: Compare data in memory with accumulator
JNC: Jump if not carry at specified memory address.
JNZ: Jump if value of specified register is not zero.
STA: This instruction is used to store the content of accumulator at given location.
RST 5: This instruction is used to set break-point for the execution.
END: This instruction is used to execute the program.
Result:  
Input:
2500-0A (Length of array)
2501-01
2502-02
2503-03
2504-10
2505-12
2506-25
2507-35
2508-45
2509-21
250A-07
Output:
2550-45 H (Largest Number)
Procedure to look output
  • After press ENTER, You will get first screen
  • Press G and Provide Initial address (as 2000)
  • Press SHIFT+4,You will get first screen again
  • Press M and Provide Input location for Input (M2500)
  • Press ENTER and Provide your Input at location (2500:10)
  • Press ENTER and provide your Input at location (2501:01) and so on…
  • Press SHIFT+4
  • Press G and Provide Initial address (as 2000)
  • Press SHIFT+4,You will get first screen again
  • Press M and Provide address for output (M2550) and press ENTER
  • You will get your desired output.

4 comments:

  1. tharun.n22 February, 2012

    obvious approach

    ReplyDelete
  2. Unknown15 June, 2012

    I understand the algorithm but i'm having a hard time coding.. the assembly syntax is new to me.. can u help me? i need to find the largest and smallest value in n input.. if it were C or java it would have been much easier..

    ReplyDelete
  3. Unknown05 September, 2013

    please help me finding the highest and the lowest value among the three inputs of the user... please .. assembly language

    ReplyDelete

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