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March 17, 2012

Write a program to transfer any number of bytes of data from one memory to another memory block.

Written by @
Apparatus Used: Microprocessor kit, Keyboards
Assumption: Let assume that we have transfer data from source to destination one by one. . Source memory block starts from memory location 2201 H whereas destination memory block starts from memory block 2301 H and length of series is 05.
Algorithm:
  • Set the counter as number of byte.
  • Initialize Source as HL Pair.
  • Initialize destination as DE Pair.
  • Move first number in accumulator.
  • Store at this number at destination and so on.
  • Increment the pointer for source as well as destination.
  • Decrement the counter and repeat until counter is zero.
Program:
Memory Add
Mnemonics
Op-code
Comments
2000
LXI
H, 2200 H
Get the length of data
2003
MOV
C,M
Set the counter
2004
LXI
H, 2201 H
Initialize source pointer
2007
LXI
D, 2301 H
Initialize destination pointer
200A
MOV
A,M
Move source data in accumulator
200B
STAX
D
Store the source data at destination
200C
INX
H
Increase the source pointer
200D
INX
D
Increase the destination pointer
200E
DCR
C
Decrement the counter by 1
200F
JNZ
200A
Repeat until counter is zero
2012
RST
5
Set Breakpoint
2013
END

End the program

Description of used instruction:
MVI: This instruction is used to store 8 bit data in specified register.
LXI: This instruction is used to store the 16-bit data in the register pair designated in the operand.
MOV: This instruction is used to copy the content from source register to destination register.
INX: This instruction is used to increment the content of specified register pair by one.
DCR: This instruction is used decrement the content of specified register by 1.
JNZ: If result is not zero it will jump to the target address.
STAX: The contents of accumulator are copied into memory location specified by the whose address specified by BC or DE register pair.
RST 5: This instruction is used to set breakpoint for the execution.
END: This instruction is used to execute the program.
Result:
Input: 2200-05 (Number of bytes), 2201-10, 2202-03, 2203-04, 2204-08, 2205-09
Output: 2301-10, 2302-03, 2303-04, 2304-08, 2305-09
Procedure to look output
  • After press ENTER, You will get first screen
  • Press G and Provide Initial address (as 2000)
  • Press SHIFT+4,You will get first screen again
  • Press M and Provide Input location for Input (M2200)
  • Press ENTER and Provide your Input at location (2200:05)
  • Press ENTER and Provide your Input at location (2201:10)
  • Press SHIFT+4
  • Press G and Provide Initial address (as 2000)
  • Press SHIFT+4,You will get first screen again
  • Press M and Provide address for output (M2300) and press ENTER
  • You will get your desired output.

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